A fire hydrant delivers water of density $\rho $ at a volume rate $L$. The water travels vertically upward through the hydrant and then does $90^o$ turn to emerge horizontally at speed $V$. The pipe and nozzle have uniform cross-section throughout. The force exerted by the water on the corner of the hydrant is

816-1262

  • A

    $\rho VL$

  • B

    zero

  • C

    $2\rho VL$

  • D

    $\sqrt 2 \rho VL$

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